5x^2+4x+27=0

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Solution for 5x^2+4x+27=0 equation: 



5x^2+4x+27=0

a = 5; b = 4; c = +27;
Δ = b2-4ac
Δ = 42-4·5·27
Δ = -524
Delta is less than zero, so there is no solution for the equation

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